What is the inverse of the function f(x) =1/9 x + 2?
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let f(x)=y
y=1/9x + 2
1/9x= y-2
x = 9(y-2)
: f(x) =y then
x = f^-1(y)
f^-1(y) = 9(y-2)
=>
f^-1(x) = 9(x-2)
y=1/9x + 2
1/9x= y-2
x = 9(y-2)
: f(x) =y then
x = f^-1(y)
f^-1(y) = 9(y-2)
=>
f^-1(x) = 9(x-2)
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