Question

What is the K.E of an electron whose de-Broglie wavelength is 5000 Å?
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Answer 1

Answer:

De-Broglie's wavelength(say ¥) is (h/mv) where h=Planck's Constant,m=mass and v=velocity.

As we know, mv=momentum(p) or p=√(2Km) where K is kinetic energy.

Using above relations,

¥=(h/√(2Km))

Put ¥=5000*(10^-10) and value of h and m=9.1*(10^-31) and get the value of K.

Explanation:

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