Question

What is the ke of 5 Moles of a gas at 27c is​

Answer 1

Answer:

18,706.05 joules or 18.706 kj.

Answer 2

Given:

Number of moles = n = 5

Temperature = T = 27+273 = 300K

To find:

Kinetic energy ( KE )

Solution:

Kinetic energy of an ideal gas is given by the formula:

$KE = \frac{3}{2}\times nRT$

n = number of moles

R = gas constant = $R = 8.314 Jmol^-^1K^-^1$

T = temperature in kelvin

$KE = 1.5 \times 8.314 \times 5\times 300$

        $= 18706.05 J = 18.706 kJ$