Question

What is the largest average velocity of blood flow in an artery of radius 2 x 10⁻³ m if the flow must remain lanimar?

Answer 1

Answer:-

Given that
Radius of the artery = 2 × 10^(-3) m

Then diameter of artery =  4 × 10^(-3)

As
Viscosity of blood = 2.084 X 10^(-3) Pa s
Density of blood  = 1.06 × 10^3 kg/m^3
Reynolds’ number for laminar flow = 2000

Then as largest average velocity with remain laminar

Vavg = (NR× viscosity )/ (density × diameter)
=( 2000 × 2.084 × 10^(-3) )/ (1.06 × 10^3 × 4 × 10^(-3))

= (4168 × 10^(-3))/( 4.24 )

= 983 × 10^(-3)

= 0.983 m/s

Answer 2

Hey mate ^_^

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Answer:
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Radius of artery = 2 × 10^-3 m

Diameter of artery = 2 × r = 2 × 2 × 10^-3 m

Density of whole blood = 1.06 × 10^3 kg/m^3

Coefficient of viscosity of blood = 2.084 × 10^3 Pa-s

For laminar flow maximum value of Reynolds number = 2000

Largest average velocity = K × n/d.D

= 2000 × 2.084 × 10³/1.06 × 4 × 10^-3

= 0.983 m/s

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Final answer : 0.98 m/s
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