Question

what is the largest number that divides 626 , 3127 and 15628 and leaves remainders of 1 , 2 and 3 respectively?

Answer 1

the number is 7.
626÷7=1 remainder
3127÷7=2 remainder
15628÷7=3 remainder

Answer 2

$\huge \fbox \blue{Solution:}$

From the question it’s understood that,

626 – 1 = 625, 3127 – 2 = 3125 and 15628 – 3 = 15625 has to be exactly divisible by the

number.

Thus, the required number should be the H.C.F of 625, 3125 and 15625.

First, consider 625 and 3125 and apply Euclid’s division lemma

3125 = 625 x 5 + 0

∴ H.C.F (625, 3125) = 625

Next, consider 625 and the third number 15625 to apply Euclid’s division lemma

15625 = 625 x 25 + 0

We get, the HCF of 625 and 15625 to be 625.

∴ H.C.F. (625, 3125, 15625) = 625

So, the required number is 625.