Question

What is the largest number that divides 63,35 and 77 leaving 7 as a remainder in each case

Answer 1

We find the LCM.

63 = 3 × 3 × 7

35 = 5 × 7

77 = 7 × 11

3 × 3 × 7 × 5 × 11 = 3465

This number divides 35, 63,77 exactly.

To get a remainder of 7 for each, we add 7 to the number.

3465 + 7 = 3472

Answer : 3472

Answer 2

63–7=56

35–7=28

77–7=70

We will find now HCF of 56, 28 ,70 :

56=2×2×2×7

28=2×2×7

70=2×5×7

HCF =2×7=14

So, the required highest number would be 14 Ans

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