Question

What is the least natural number you have to add to 1024 to get a multiple of 181

Answer 1

181*5=905
181*6=1086

So, we have to add (1086-1024) = 62 to 1024 to make it divisible by 181

Answer 2

answer : 62.

explanation : we have to find least natural number, X such that (1024 + X) will be multiple of 181.

first of all, tell me 181 is prime number or composite number ?

of course , 181 is a prime number because it can't break into two or more integral parts.

now, let's divide 1024 by 181

181)1024(5

905

-------

119

=> remainder = 119

we have to add a number in 1024 so that it will be divisible by 181 = 181 - 119 = 62.

let's see how, 181 × 6 = 1086 and 1024 + 62 = 1086 .

hence, if we add 62 in 1024 , it is divisible by 181. or, in simple way , if we add 62 in 1024 we get a multiple of 181.

hence, answer is 62.