Question

What is the least no. which when divided by 7,8 and 18 leaves a remainder 4 in each case?

Answer 1

Answer :

508 is the least number that divides 7,8 and 18 leaving the remainder 4 in each case.

$\rule{100}2$

In order to find the least number, we've to find the L.C.M of 7, 8 and 18.

• 7 = 7 × 1
• 8 = 2³
• 18 = 2 × 3²

→ L.C.M = 2³ × 3² × 7

             = 72 × 7

             = 504

Now, add 4 in 504.

504 + 4

= 508

Therefore,

508 is the least number that divides 7, 8 and 18, leaving the remainder 4 in each case.

$\rule{200}2$