Question

What is the least number of complete years in which a sum of money put out at 20%
will be more than double? ​

Answer 1

Answer:

answer will be 4

Step-by-step explanation:

p(1+20/100)n>2p=(6/5)n>2

now,(6/5*6/5*6/5*6/5)>2

so, n=4year.