Math, asked by saumyaashri, 1 year ago

What is the least number of four digits when increased by 7 divisible by 35,48 and 56?


GrumpyBear: Okay im kidding the answer is 38. :)
pmanghnani4p7hsne: Hi me prachi

Answers

Answered by manaswidewanp7hv4g
0
hey hope it helps you....
Attachments:

GrumpyBear: I cant even read one word in that pic...........
manaswidewanp7hv4g: sad its wrong anyways ... you are supposed to add 7 to each of these numbers then calculate lcm and if its not 4 digit keep multiplying it by 2 then 3 and so on
saumyaashri: ty for help
manaswidewanp7hv4g: glad but make sure u add 7 and not subtract it
saumyaashri: frst we have to take lcm of this all than the ans will be 1680 than after that we have to substract 7 from them nd we'll got the ans
manaswidewanp7hv4g: yes thats true m stupid lol
Answered by rahulshah41065
0

Answer:1673 or 1680


Step-by-step explanation:

LCM of 35,48 & 56 is 1680. It is the smallest number divisible by all 3 numbers. If number 1673 is increased by 7, we get 1680.


So the answer is 1680.

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