What is the least number of four digits when increased by 7 divisible by 35,48 and 56?
GrumpyBear:
Okay im kidding the answer is 38. :)
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hey hope it helps you....
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Answer:1673 or 1680
Step-by-step explanation:
LCM of 35,48 & 56 is 1680. It is the smallest number divisible by all 3 numbers. If number 1673 is increased by 7, we get 1680.
So the answer is 1680.
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