Question

What is the least number That is divisible by all the natural number from 1 to 10 and how



Tell me PLZZ by step by step

Answer 1

LCM of 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
First write the prime factorization of each number.

1=1. (one is not prime).

2=2

3=3

4=2 x 2

5=5

6=3 x 2

7=7

8=2 x2x 2

9 = 3 x 3

10 = 5 x 2


multiply the different primes the maximum number of times they occur in an example. So for the number 2, we see that 8 is 2 times 2 times 2 .This ensures the 2’s in 2, 4, 6, and 10 are “covered.” We don’t need to multiply by any more twos.

Continuing this process we obtain

(2x2x2)(3x3)(5)(7)=2520

Your answer is 2520

IF IT IS CORRECT MARK BRAINLIEST ✌️❤️

Answer 2

hi

we have to find What is the least number That is divisible by all the natural number from 1 to 10 and how

so no.from  1 to 10

=>1,2,3,4,5,6,7,8,9,10

now we have to find the lcm of these numbers

lets do it by prime factorsiation

1=1.

2=2

3=3

4=2 x 2

5=5

6=3 x 2

7=7

8=2 x2x 2

9 = 3 x 3

10 = 5 x 2

so now lcm

=> 2 x 2 x 2*3 x 3*5*7=2520

hence 2520  is the 

the least number That is divisible by all the natural number from 1 to 10

hope it helps u

:)