Question

What is the least number that must be subtracted from 3000 so that the difference is divisible exactly by 32,36 and 48

Answer 1

Answer:

Step-by-step explanation:

This is write answer ok

Answer 2

Answer: The correct answer is 120.

Step-by-step explanation:

LCM of 32, 36 and 48 = 288

Here we  will find the factors of the numbers 32, 36 and 48.

32 = 2×2×2×2×2

36 = 2×2×3×3

48 = 2×2×2×2×3

Thus after factorising obtained LCM is  2×2×2×2×2×3×3 is 288.

Multiple of 288 will be exactly divisible by 32,36 and 48

Now let us divide 3000/288 = 10.41

Thus, the number which is divisible by 32,36, 48 should be

288×10 = 2880

After subtracting we get 3000 - 2880 = 120

Hence, the number 120 should be reduced from 3000 so that 2880 is divisible by 32,36 and 48.

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