Question

What is the least number that should be subtracted from 2810 to obtain a number exactly divisible by 17
1
3
5
7

Answer 1

Answer:

5 will be the answer

hope this will help

Answer 2

5 is the least number subtracted from 2810 and exactly divisible by 17

2810-5=2805; 2805÷17=0 remainder

Step-by-step explanation:

Given:

The least number that subtracted from 2810 to obtain a number exactly divisible by 17

To find:

Number exactly divisible by 17 which is subtracted from 2810

Solution:

• In the problem, it is clear that we need to find the small number that should be subtracted from 2810 and that exactly divided by 17.
• We need to analyze the options from (1,3,5,7)

If the least number is 1 means it leaves a remainder which in turn clear that it is not exactly divisible by 17.

2810-1⇒2809

          ⇒2809÷17

If the least number must be 3 means, it leaves a remainder which in turn clear that it is not exactly divisible by 17.    

2810-3⇒2807

          ⇒2807÷17

If the least number is 5 means it is exactly divisible by 17. So the smallest number that should be subtracted from 2810 is 5.

2810-5⇒2805

           ⇒2805÷17

quotient⇒165

remainder⇒0

Hence,

The least number is 5

2810-5=2805; 2805÷17=0 remainder.