Question

What is the least number that should be subtracted from 3592 to obtain a number exactly divisible by 19?

Answer 1

Answer:

1 is the least number that must be substracted from 3592 to get a multiple of 19.

Step-by-step explanation:

Given:- The given number is 3592.

To Find:- The least number that must be substracted from 3592 to obtain a multiple of 19.

Solution:-

The given number is 3592.

When we divide 3592 by 19, we get Quotient = 189 and Remainder = 1.

3592 = 3591 + 1

         = (189 × 19) + 1

Since 189 times 19 is equal to 3591, which means 3591 is a multiple of 19.

So we need to substract 1 from 3592 to get 3591.

Therefore, the least number which we need to substract from 3592 to get a multiple of 19 is 1.

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Answer 2

Concept

Remainder is that integer which remains left over after dividing a number by another

Given

a number 3592.

Find

We need to find the least number that must be subtracted from 3592 so that it is exactly divisible by 19

Solution

we have

3592

Let us first divide 3592 by 19

On doing so we get a remainder of 1

thus, if we subtract 1 to 3592, it will be completely divisible by 19

3592 - 1 =3592

To check the answer, we further divide 3593 by 19

On doing so we find that the remainder comes out to be 0

19 * 189 = 3592

Therefore, the least number that should be subtracted from 3592 to obtain a number exactly divisible by 19 is 1.

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