Question

What is the least number which when divided by 3,8,11,21 and 27 leaves a remainder of 5 in each case.

Answer 1

• At first find the L.C.M of 3,8,11,21 and  27

                         we get = 16632

• The required no. is 16632 + 5 = 16637
• It is the least no. ,When divided by 3 , 8 , 11 , 21 and 27 leaves a remainder of 5 in each case.

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Answer 2

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Here is your answer.......

=> First of all ,
we have to find the LCM of 3 , 8 , 11 , 22 and 27 ........

=> LCM by Prime Factorization method :-

3 = 3

8 = 2×2×2

11 = 11

21 = 3 × 7

27 = 3×3×3

so the LCM ( lowest common factor ) is 16632

=> Now , add remainder 5 to LCM then we will get the no. 16632 + 5 = 16637 which leaves a remainder 5 in each case.......

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