what is the least number which when divided by the numbers 3 5 6 8 10 and 12 in each case leaves 2 as remainder but which when divided by 13 leaves no remainder?
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120 is the LCM of 3,5,6,8,10,12. 962 is divisible by 13. What is the least number which when divided by the number 3, 5, 6, 8, 10 and 12 leaves in each case a remainder 2 but when divided by 22 leaves no remainder?
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