- What is the least number which when divided by the numbers 3,
5, 6, 8, 10 and 12 leaves in each case a remainder 2 but which when
divided by 13 leaves no remainder?
WHOEVER ANSWER THIS QUESTION CORRECT I WILL MARK THE BRAINLIEST ^_^
Answers
Answered by
0
Answer:
LCM(3,5,6,8,10,12)=120
As it leaves 2 as remainder the number must be something in the form= 120x + 2
We will find the least value for x
120x +2 = 117x +3x +2
117 is divisible by 13. So x=8
So the number will be
120*8 + 2 =962
Hope it helps.. Pls mark as brainliest
Answered by
0
Answer:
6 6 6 6 6 6
Step-by-step explanation:
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