Question

What is the length of a cuboid having volume 12503 and whose length, breadth and height are in the ratio 5:2:1?

(step by step expiation please)​

Answer 1

Solution :-

$\sf {\dag} The\;Dimensions\;are:$

$\sf \leadsto Length(l) = 5x$

$\sf \leadsto Breadth (b)= 2x$

$\sf \leadsto Height(h) = x$

$\sf {\dag} \; Volume (Given) = 12503$

$\sf \rightarrow l \times b \times h = 12503$

$\sf \rightarrow 5x \times 2x \times x = 12503$

$\sf \rightarrow 10x^{3} = 12503$

$\sf \rightarrow x^{3} = \dfrac{12503}{10}$

$\sf \rightarrow x^{3} = 1250.3$

$\sf \rightarrow x =$ ∛1250.3

$\sf \rightarrow x =10.77$

∴ Length is ( 10.77 × 5 ) = 53.85

Answer 2

Answer:

length=53.85

breadth=21.54

height=10.77

Step-by-step explanation:

l×b×h=volume of cuboid

5x×2x×x=12503

10x^3=12503

x=10.77

length=10.77×5=53.85m