WHAT IS THE LENGTH OF A RECTANGLE IF THE WIDTH IS 8CM AND THE DIAGONAL IS 17CM?
Answers
Answered by
1
Answer:
Using Pythagoras theorem
8^2+b^2=17^2, where b is the breadth of the rectangle
64+b^2=289
b^2=289–64=225 cm^2
b=15 cm
Perimeter= 2(8+15)=46 cm
Since 15 > 8, we rename , length= 15 cm and breadth = 8 cm
Answered by
1
Answer:
15 cm
Step-by-step explanation:
Given,
Width = Breadth ( b ) = 8 cm
Diagonal ( d ) = 17 cm
To find : Length ( l ) = ?
l^2 + b^2 = d^2
l^2 = d^2 - b^2
= 17^2 - 8^2
= 289 - 64
l^2 = 225
l = √225
l = 15 cm
Therefore, Length ( l ) = 15 cm
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