Question

What is the length of a rectangle whose breadth is 15 cm and area is 900 square CM

Answer 1

$\huge\mathbb{\underline{\underline{\purple{SOLUTION:-}}}}$

$\large\mathtt{\underline{\red{Given:-}}}$

Breadth=15cm

$\rm Area =900cm{}^{2}$

we have to find the length

Let the length be x

And we know that the area of rectangle=Length ×breadth

Then the length be x and breadth=15

$\large\mathtt{\underline{\underline{\red{According\:to\: question:-}}}}$

$\sf Area\:of\: rectangle=L\times B\\ \\ \sf\leadsto where L=length\:and\:B=Breadth\\ \\ \sf Area=L\times B\\ \\ \sf\longrightarrow 900=15\times x\\ \\ \sf\longrightarrow\frac{900}{15}=x\\ \\ \sf\leadsto 60=x$

The value of x is 60cm

$\sf\large\underline{\red{Verification:-}}$

Area =L×B

$\sf 900=15×60\\ \\ \sf\implies 900=900\\ \\ \sf L.H.S=R.H.S$

So the length of rectangle=60cm

$\huge\boxed{\underline{\blue{\sf{Length=60cm}}}}$

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Answer 2

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✨$\underline \mathbb{GIVEN}$

✨Breadth=15cm

✨$area = 900c {m}^{2}$

✨we have to find the length

✨Let the length be x

✨And we know that the area of rectangle=Length ×breadth

✨Then the length be x and breadth=15

✨ACCORDING TO QUESTION:

✨Areaofrectangle=L×B

✨whereL=lengthandB=Breadth

✨Area=L×B

✨900=15×x

✨$= > 900 \div 15 \times x$

✨$= > 900 \div 15 = x$

✨$x = 60$

✨THE VALUE OF X IS 60 CM.

✨$\underline \mathbb{VERIFICATION}$

✨Area =L×B

✨$900 = 15 \times 60$

✨$= > 900 = 900$

✨L.H.S=R.H.S

✨So the length of rectangle=60cm

▀▄ [_ANSWER_]▄▀

✨LENGTH = 60 cm

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