Question

What is the length of a simple
pendulum which has time period of
1sec? (take r² = 9.87)​

Answer 1

Answer:

$t = 2\pi \times \sqrt{ \frac{l}{g} }$

$1 = 2\pi \sqrt{ \frac{l}{9.8} }$

$(\frac{1}{2\pi} {)}^{2} = \frac{l}{9.8}$

l = 1 / 4 m