What is the length of chord which is at distance of 6cm from the center of the circle of radius 10 cm?
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Given = distance from the center of circle =6 cm,
radius = 10 cm
To find = length of chord =?
solution = consider, o is the center of circle ,
and the point on the chord where the the distance is perpendicular to the base be ' A and B.
Now, see in triangle OAB
it is right angle triangle .
Hence, by Pythagoras theorem.
(OB) 2= (OA) 2+(ab) 2.
= 100-36 =( AB) 2
therefore, A B=8 cm.
therefore, the length of chord =8 +8 = '16' cm.
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