What is the length of outer boundary of the park shown in the figure? What will be the total cost of fencing it at the rate of Rs 20 per metre? There is a rectangular flower bed in the center of the park. Find the cost of managing the flower bed at the rate of Rs 50 per square metre.
Answers
Answer:
400000/-
Step-by-step explanation:
Addition of all Sides of Given figure is called perimeter
∴ Perimeter of the given figure =(200+300+80+300+200+260)m=1340 m
∴ Total cost of fencing it at the rate of Rs.20 per meter
=Rs.(1340×20)=Rs.26800
∴ Area of the flower bed =(100×80)m
2
=8000 m
2
Now, cost of manuring the flower bed at the rate of Rs.50 per square meter =Rs.(50×8000)=Rs.400000.
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Answer:
400000.
Step-by-step explanation:
Addition of all Sides of Given figure is called perimeter
∴ Perimeter of the given figure =(200+300+80+300+200+260)m=1340 m
∴ Total cost of fencing it at the rate of Rs.20 per meter
=Rs.(1340×20)=Rs.26800
∴ Area of the flower bed =(100×80)m
2
=8000 m
2
Now, cost of manuring the flower bed at the rate of Rs.50 per square meter =Rs.(50×8000)=Rs.400000.
HOPE IT HELPS YOU DEAR.