Question

what is the length of the edge of a cube whose volume is 729 square​

Answer 1

Answer:

9 units

Step-by-step explanation:

As volume of cube =a³

So ∛729 =9

Answer 2

Step-by-step explanation:

Question :-

• Find the side of cube whose volume is 729 cm³.

To Find :-

• Side of cube.

Solution :-

Given :

• Volume = 729 cm³

By using the formula,

${\sf{\longrightarrow Volume\ of\ cube\ =\ a^3}}$

Where,

• a = length of the side

According to the question, by using the formula, we get :

${\sf{\longrightarrow Volume\ of\ cube\ =\ a^3}}$

${\sf{\longrightarrow 729\ =\ a^3}}$

${\sf{\longrightarrow \sqrt[3]{729}\ =\ a}}$

${\sf{\longrightarrow 9\ =\ a}}$

${\sf{\longrightarrow a\ =\ 9\ cm}}$

$\therefore$ Hence, side of cube is 9 cm.

More To Know :-

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$