what is the length of the rectangle if the perimeter is 309.2 and width is 71.2
Answers
Answered by
4
Let the length be x
ATP ,
2(x+71.2)=309.2
x+71.2=309.2/2
x+71.2=154.6
x=154.6-71.2=83.4
Hence , it's length is 83.4
ATP ,
2(x+71.2)=309.2
x+71.2=309.2/2
x+71.2=154.6
x=154.6-71.2=83.4
Hence , it's length is 83.4
Answered by
1
Let the length be l
using the formula 2(l+b)
2(l+71.2)=309.2
l+71.2=309.2/2
l+71.2=154.6
l=154.6-71.2=83.4
Hence , it's length is 83.4
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