What is the limitation of the reaction zn +2HCL GIVES ZNCL2+H2
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1.85 g of hydrogen will form.
Explanation:
1. Write the balanced equation.
Zn+2HCl→ZnCl2+H2
2. Calculate the moles of Zn.
Moles of Zn=30.0g Zn×1 mol Zn65.38g Zn=0.4589 mol Zn
3. Calculate the moles of H2.
Moles of H2=0.4589mol Zn×2 mol H21mol Zn=0.9177 mol H2
4. Calculate the mass of H2.
Mass of H2=0.9177mol H2×2.016 g H21mol H2=1.85 g H2
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