What is the limitation of the reaction zn +2HCL GIVES ZNCL2+H2
Answers
Zn + 2 HCl - - - - - - - - -> ZnCl2+ H2
For different concentrations :
0.3 moles Zn x 1 mole H2 / 1 mole Zn = 0.3 moles H2
0.52 moles H2 x 1 mole H2 / 2 moles HCl = 0.26 mole H2
Hence, HCl will be the limiting reagent in the reaction and Zn will be excess reagent. Amount of hydrogen produced will be = 0.26 moles.
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.Aqsaahmed19945Virtuoso
Zn + 2 HCl - - - - - - - - -> ZnCl2+ H2
For different concentrations :
0.3 moles Zn x 1 mole H2 / 1 mole Zn = 0.3 moles H2
0.52 moles H2 x 1 mole H2 / 2 moles HCl = 0.26 mole H2
Hence, HCl will be the limiting reagent in the reaction and Zn will be excess reagent. Amount of hydrogen produced will be = 0.26 moles.
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