Question

What is the limiting reactant if 4.0 g of NH3 react with 8.0 g of oxygen

Answer 1

NH3

i guess this as a limiting reagent

Answer 2

The limiting reactant is oxygen gas

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$     .....(1)

• For ammonia:

Given mass of ammonia = 4.0 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

$\text{Moles of ammonia}=\frac{4.0g}{17g/mol}=0.235mol$

• For oxygen gas:

Given mass of oxygen gas = 8.0 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{8.0g}{32g/mol}=0.25mol$

The chemical equation for the reaction of ammonia and oxygen gas follows:

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)$

By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 4 moles of ammonia

So, 0.25 moles of oxygen gas will react with = $\frac{4}{5}\times 0.25=0.2mol$ of ammonia

As, given amount of ammonia is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

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