Question

what is the linear acceleration( in m/s2) of the rope if the rope is pulled with a force of 30 N. ​

Answer 1

Answer:

The moment of inertia of the hollow cylinder about its geometric axis:

I=mr

2

=3×0.4

2

kgm

2

The Torque developed is given by:

τ=rF=0.4×30Nm=12Nm

We know that the relation between the torque and angular acceleration is:

τ=Iα

⟹α=25rads

−2

Thus linear acceleration(a)=rα=0.4×25m/s

2

=10m/s

2