Question

what is the lmc of two numberes if their hcf is2 and the product is 112?

Answer 1

let the numbers be 'a' and 'b'

Given that
HCF(a,b)=2
and
ab=112

We know that
ab=LCM(a,b)×HCF(a,b)
i.e.
112=LCM(a,b) × 2
LCM(a,b) =56

Answer 2

Given that HCF of two numbers  = 2.

Given that Product of two numbers = 112.

We know that LCM * HCF of two numbers = Product of two numbers

                        LCM * 2 = 112

                        LCM = 112/2

                                = 56.


Therefore the LCM of two numbers = 56.


Hope this helps!