Question

what is the load factor against collapse of ultimate tensile strength of tie is 1218 kN and design tensile load is 600 KN​

Answer 1

Given:

The ultimate tensile strength of tie, $\[\sigma_{max}\]$ = 1218 kN

The design tensile strength of tie, $\[\sigma_{design}\]$ = 600 kN

To find:

We have to find the load factor against collapse, which is also known as Factor of safety (FOS).

Solution:

Now,

The factor of safety is given by the formula,

$FOS = \frac{Maximum\:tensile\:strength}{Design\:tensile\:load}$

Hence, replacing the values from given to the above formula, we get,

The factor of Safety is given by

$FOS=\frac{\sigma_{max} }{\sigma_{design}}$

Then, replacing the numerical values in the above equation, we get,

⇒$FOS=\frac{1218}{600}$

∴$FOS = 2.03$

The load factor against collapse (factor of safety) is $2.03$.