Question

what is the longest pole that can be put in a room of dimensions l= 10cm b=10cm h=5cm

Answer 1

$\huge\mathfrak\red{Answer}$

The longest pole that can be put in a room will be equal to its diagonal:

Hence, longest length of pole

$\begin{gathered}longest \: length \: of \: pole = \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} } \\ = \sqrt{ {10}^{2} + {10}^{2} + {5}^{2} } \\ = \sqrt{ 100 + 100 + 25 } \\ = \sqrt{ 225 } \\ = 15 \: cm. \\ \end{gathered} </p><p>longestlengthofpole= </p><p>l$

Step-by-step explanation:

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Answer 2

Answer:

length of pole  $=\sqrt( l^{2} + b^{2} +h^{2} )\\=\sqrt( 10^{2} +10^2+5^2)\\=\sqrt225\\=25 cm$