Question

what is the lowest resistance that can be obtained by combing four coils of resistors of 4ohm 8ohm 12ohm and 24ohm​

Answer 1

2 ohm

Explanation:

Minimum resistance is obtained when resistors are connected in parallel

So, 1/R=1/4+1/8+1/12+1/24

12/24=1/2

So R=equivalent resistance= 2ohm

Answer 2

Answer:

2 Ω is the lowest resistance that can be obtained by combing four coils of resistors of 4ohm 8ohm 12ohm and 24ohm​.

Explanation:

If these coils are connected in parallel, then the equivalent resistance will be the lowest, given by

1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4

⇒1/R = 1/4 + 1/8 + 1/12 + 1/24

⇒1/R = (6+3+2+1) / 24

⇒1/R = 12 / 24 = 1/2

⇒R=2 Ω

∴ 2 Ω is the lowest  resistance.

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