Question

What is the magnetization of a bar magnet having length 6cm and area of cross section 5cm square ? ( M net = 1)

Answer 1

Explanation:

3.3×10⁴A/m

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Answer 2

Given:

• Length = 6 cm = 6×$10^{-2}$ m
• Area of cross-section = 5 $cm^2$ =  5×$10^{-4}$  $m^2$
• $M_{net}$ = 1 A$m^2$

To Find:

• The magnetization of a bar magnet.

Solution:

The formula to find the magnetization of a bar magnet is given by,

Magnetization = $M_{net}$/v → {equation 1}

Where "v = length×area of cross-section" and "$M_{net}$" is the magnetic moment.

On substituting the given values in equation 1 we get,

⇒ Magnetization = 1/( 6×$10^{-2}$ × 5 × $10^{-4}$) {multiplying the terms in bracket}

⇒ Magnetization = 1/(3 × $10^{-5}$)  {dividing the terms}

⇒ magnetization = 3.33×$10^{4}$ = A/m

∴ The magnetization of a bar magnet =  3.33×$10^{4}$ = A/m