What is the magnitude of current that flows througha wire if 0.5mole of electrons flow through it in 30 minutes
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No. of electrons in 0.5 mole is =0.5*6.023*10²³ electrons
Total charge which is ⇒q=ne
q=0.5*6.023*10²³*1.6*10⁻¹⁹ C
t=30 min=1800 seconds=1.8*10³ seconds
Current which is, I=q/t
I=(0.5*6.023*10²³*1.6*10⁻¹⁹ C)/(1.8*10³ seconds)
I=26.8 A
Magnitude of current is 26.8 Ampere.
Total charge which is ⇒q=ne
q=0.5*6.023*10²³*1.6*10⁻¹⁹ C
t=30 min=1800 seconds=1.8*10³ seconds
Current which is, I=q/t
I=(0.5*6.023*10²³*1.6*10⁻¹⁹ C)/(1.8*10³ seconds)
I=26.8 A
Magnitude of current is 26.8 Ampere.
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