Question

What is the magnitude of the gravitational force between the Earth and a 1 kg object on its surface ? (Mass of Earth is 6×10^24 kg and radius of the Earth is 6.4×10^6m)​.


━━━━━━━━━━━━━━━━━━━

Lᴀꜱᴛ Qᴜᴇꜱᴛɪᴏɴ ᴏɴ ʙʀᴀɪɴʟʏ !!

❝ Dont spam please ❞​

Answer 1

Explanation:

Given :       Mass of earth    M = 6×1024 kg

                   Mass of object    m = 1 kg

                  Radius of earth       R = 6.4×106 m 

Force of gravitation between them, F = GMm/R²

F = 6.67 ×10^-11 ×(6×10²⁴) ×1 / (6.4 × 10^6)² = 9.77N

Hope this helps you!!

Answer 2

$\huge \frak \red {ANSWER} </p><p></p><p>$

$Mass \: of \: earth \: \: M=6× {10}^{24} </p><p> kg \\ </p><p> Mass \: of \: object \: \: m=1 kg \\ </p><p> Radius \: of \: earth = R=6.4× {10}^{6} m$

$Force \: of \: gravitation \: between \: them \: , F= </p><p> \frac{GMm}{ {R}^{2} } </p><p> </p><p></p><p>$

$F= \: \frac{6.67 \times {10}^{ - 11} \: \times (6 \times {10}^{24} )}{(6.4 \times {10}^{6} ) ^{2} }$

$9.77 \: N$

$\small \underline \frak \red {hope \: it \: helps \: u \: lot \: }$