Question

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10^24 kg and radius of the earth is 6.4 × 10^6 m).​

Answer 1

magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10^24 kg and radius of the earth is 6.4 × 10^6 m).

Answer 2

Hello mate__ here is your answer --

Mass of Earth, M = 6 × 10^24 kg

Mass of object, m = 1 kg

Universal gravitational constant,

G = 6.7 × 10^−11 Nm^2 kg^−2

r = radius of the Earth (R) ( ob. is on the surface of earth)

r = R = 6.4 × 10^6 m

Therefore, the gravitational force

F = GMm / r^2

= (6.7 × 10^-7 × 6 × 10^24 × 1)/ (6.4 ×10^4)^2

= 9.8 N

I hope, this will help you.☺

Thank you______❤

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