What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10^24 kg and radius of the earth is 6.4 × 10^6 m).
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magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10^24 kg and radius of the earth is 6.4 × 10^6 m).
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Hello mate__ here is your answer --
Mass of Earth, M = 6 × 10^24 kg
Mass of object, m = 1 kg
Universal gravitational constant,
G = 6.7 × 10^−11 Nm^2 kg^−2
r = radius of the Earth (R) ( ob. is on the surface of earth)
r = R = 6.4 × 10^6 m
Therefore, the gravitational force
F = GMm / r^2
= (6.7 × 10^-7 × 6 × 10^24 × 1)/ (6.4 ×10^4)^2
= 9.8 N
I hope, this will help you.☺
Thank you______❤
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