Physics, asked by rociogonzalezdlt, 9 months ago

What is the magnitude of the repulsive force between two pith balls (small, light balls that are easily charged) that are 0.08 m apart and have equal charges of 3.0 x 10 -8C?

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Answered by ksonakshi70
0

Answer:

according to electrostatic force

F = 9×10^9 × 3.0×10^-8 ×3.0×10-8 /(0.08)^2 N

Answered by Anonymous
0

Answer:

Hey mate your answer is given below

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