What is the magnitude of the repulsive force between two pith balls (small, light balls that are easily charged) that are 0.08 m apart and have equal charges of 3.0 x 10 -8C?
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1
Answer:
hey mate .. plzz refer to attachment ..
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Answer:
1.26*10^-3
Explanation:
f=kq1q2/r^2
where k= 9*10^9
q1=q2=3*10^-8
r=8*10^-2.
Substitute
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