Question

what is the magnitude of vector A=3i^ -k^

Answer 1

☆☆ AS-SALAMU-ALYKUM☆☆

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MAGNITUDE OF RESULTANT A IS :-

|A|=square root 3^2 + (_1)^2

|A| =square root 9 + 1

|A| = square root 10

|A| = 3.16

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♡♤♡ INSHALLAH IT WILL HELP U ♡♤♡

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GOOD NIGHT HAVE SWEET DREAMS ☺☺☺

Answer 2

Answer:

The magnitude of vector is $\sqrt{10}units.$

Explanation:

• Let us consider a vector $ai+bj+ck$
• The magnitude of vector = $\sqrt{a^{2}+b^{2}+c^{2} }$

now,

we have  given vector, $A = 3i-k$

$Magnitude =\sqrt{3^{2}+ (-1)^{2} }$

                  $= \sqrt{9+ 1} \\= \sqrt{10} units$

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