Question

What is the mass in grams occupied by 3.04 L Ar gas at STP? Note that volume of 1.0 mol of Ar gas at STP = 22.4 L.Use molar mass of 39.95 g/mol for Ar. Report answer to 3 sig figs.

Answer 1

Answer:

Problem #1: Determine the volume of occupied by 2.34 grams of carbon dioxide gas at STP.

Solution:

1) Rearrange PV = nRT to this:

V = nRT / P

2) Substitute:

V = [(2.34 g / 44.0 g mol¯1) (0.08206 L atm mol¯1 K¯1) (273.0 K)] / 1.00 atm

V = 1.19 L (to three significant figures)

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