Question

What is the mass in grams of 0.100 mole of glucose C6H1206?

Answer 1

( Atomic mass of C = 12u ; H = 1u ; O = 16u )

★ 1 mole of glucose = Molecular mass of C6H1206

= 12 × 6 + 1 × 12 + 16 × 6

= 72 + 12 + 96

= 180 u ( gram )

Now,

1 mole of glucose atoms = 180 g

0.100 moles of glucose atoms

= 180 × 0.100 ) g

= ( 180 × 100/1000 ) g

= ( 18 × 100/100 ) g

= 18 g

Thus, the mass of 0.100 moles of glucose ( C6H1206 ) atoms is 18 g.