Question

what is the mass in grams of 3.47 moles of nacl​

Answer 1

Answer:

Mass of 1 mole of NaCl = 23 + 35.5 = 58.5 g

So, mass of 3.47 moles of NaCl = 3.47 * 58.5 g

= 202.995 g

Answer 2

Answer:

a 1 M solution of sodium chloride, NaCl (1 M), would contain 1

mole of NaCl (= 22.99 + 35.45 g) dissolved in enough water so that the final

volume of the solution was 1 litre.

Note: The molarity applies to the solute formula. Thus, while the amount of sodium

chloride, NaCl, dissolved is 1 mole, there are actually 1 mole of Na+

ions and 1

mole of Cl–

ions present in that solution. Similarly, a 1 M solution of barium

chloride, BaCl2

, contains 1 mole of the solute per litre of solution which would

provide 1 mole of Ba2+ ions and 2 mole of Cl–

ions per litre of solution.

The following examples show how molarity, volume and moles are related. If two

of these quantities are known, then the third can be deduced.