What is the mass of 1 mole of nitrogen atom , 4 mole of aluminum atoms (atomic mass of aluminium =27 ), 10 mole of sodium sulphate (na2so3)?
Answers
Answer:
a) n=m/M
m=n×M. N=14u
m=1×14
m=14
b) n=m/M
m=n×M. Al=27
m=4×27
m=108
c) n=m/M. Na2SO3
m=n×M. 23×2+32+16×3
m=10×126 46+32+48
m=1260.
Question :-
What is the mass of
(a) 1 mole of nitrogen atoms?
(b) 4 moles of aluminium atoms (Atomic mass of aluminium = 27)?
(c) 10 moles of sodium sulphite (Na2S03)?
Answer :-
(a) Mass of 1 mole of nitrogen atoms = 14 g
(b) 4 moles of aluminium atoms
Mass of 1 mole of aluminium atoms = 27 g
∴ Mass of 4 moles of aluminium atoms = 27 x 4 = 108 g
(c) 10 moles of sodium sulphite (Na2SO3)
Mass of 1 mole of Na2SO3 = 2 x 23 + 32 + 3 x 16 = 46 + 32 + 48 = 126 g
∴ Mass of 10 moles of Na2SO3 = 126 x 10 = 1260 g
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