Question

What is the mass of 2.486x10^24 atoms of neon?

A) 4.130 g Ne
B) 0.2046 g Ne
C)83.33 g Ne
D) 8.333 g Ne

Answer 1

answer is c

please see the above attached file

Answer 2

The mass of $2.486\times 10^{24}$ atoms of neon is 83.33 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given atoms}}{\text{Avogadro's number}}=\frac{ 2.486\times 10^{24}}{6.023\times 10^{23}}=4.128moles$

1 mole of neon weighs = 20.18 g

4.128 moles of neon weigh = $\frac{20.18}{1}\times 4.128=83.33g$

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