Question

What is the mass of a solid Iron wrecking ball of radius 18cm. If the density of Iron is 7.8g/cm²​

Answer 1

Answer:

this is the answer apply same formula

Answer 2

Answer:

The mass of the solid iron ball is 190.5kg.

Explanation:

We will use the following formula to solve this question which is given as,

$\rho=\frac{m}{V}$       (1)

Where,

ρ=density of the material

m=mass of the material

V=volume of the material

From the question we have,

Radius(r)=18cm=18×10⁻²m

Density(ρ)=7.8g/cm³=7.8×10³kg/m³

The volume of the iron ball is given as,

$V=\frac{4}{3}\pi r^3$

$V=\frac{4}{3}\pi\times (18)^3$        (2)

By substituting equation (2) and the value of ρ in equation (1) we get;

$7.8=\frac{m}{\frac{4}{3}\pi\times (18)^3}$

$m=7.8\times 10^3\times \frac{4}{3}\pi\times (18\times 10^-^2)^3$

$m=190.449kg \approx190.5kg$

Hence, the mass of the solid iron ball is 190.5kg.