Question

what is the mass of chlorine gas that can produced from 2.4 litres of hydrogen gas at s.t.p.
Given H²+Cl² -----> HCl​

Answer 1

Answer:

Thus, when 22. 4 liters of H2(g) is mixed with 11. 2 liters of Cl2(g), each at STP, the moles of HCl(g) formed is equal to 1 mol of HCl(g).

Answer 2

Explanation:

At STP, 1 mole of any gas occupies a volume of 22.4 L.

22.4lt

H

2

+

11.2lt

Cl

2

→2HCl

Limiting reagent is Cl

2

.

1 mole of chlorine forms 2 moles of HCl.

Hence, 0.5 moles of chlorine will form 1 mole of HCl.

Thus, when 22.4 liters of H

2

(g) is mixed with 11.2 liters of Cl

2

(g), each at STP, the moles of HCl(g) formed is equal to 1 mol of HCl(g).