Question

What is the mass of copper sulphate present in 500 ml of 25% solution of it at 298 K.

Answer 1

Answer:

100 g of dilute solution of CuSO4 contain

=1.2×10=12.0gCuSO4

Mass of water present in dilute solution

=(100−12)=88g

To saturate 100 g of water, CuSO4 required =25g

So, to saturate 88 g of water, CuSO4required =10025×88=22g

Thus, the mass of CuSO4 to be added to 100 g of dilute solution to saturate it =(22−12)=10g.