What is the mass of glucose required to produce 44g of Co2 on complete combustion
Answers
Answered by
70
Mass of glucose is 180g
Mass of CO2 formed in reaction is 44 x 6 is equal to264g
So glucose required is 180 x 44 divided by 264 gives 30 g
Answer is 30g
Mass of CO2 formed in reaction is 44 x 6 is equal to264g
So glucose required is 180 x 44 divided by 264 gives 30 g
Answer is 30g
Answered by
46
HI
C6H12O6 + 6 O2 --->6 H2O +6 CO2
Hence 180g of glucose is needed to produce 264g of co2
So, for producing 44g of CO2, 180 x 64 / 264g of glucose needed = 180/6= 30g.
hence 30g of glocose required to produce 44g of CO2 on complete combution.
C6H12O6 + 6 O2 --->6 H2O +6 CO2
Hence 180g of glucose is needed to produce 264g of co2
So, for producing 44g of CO2, 180 x 64 / 264g of glucose needed = 180/6= 30g.
hence 30g of glocose required to produce 44g of CO2 on complete combution.
Similar questions